Current amp:
The current amp puts about 2100 joules into two 8 inch lamps (total).  2900V in
two 250uf caps, one for each lamp.
Voltage was increased to 2900V, 2102J electrical input.   (measurment error, 
true voltage is 2900V not 3300V.)

It gets a little weird at 2400V, which is 1440 joules total for both lamps.  

The lamps are 200mm long by 5mm diameter (arc), Ko is 51.2.  

To put 2000J into a single lamp with a single 260uf cap would require 4000 volts.
Which is very close to the small cap's rating.  (and totaly exceeds the lamp's rating)

What are the beam diameters into and out of the amp?  I believe a lot of the volume
is not being utilized.

The ruby index of refraction is 1.768 to 1.772 (W)  1.760 to 1.763 (E)
So its effective length for optical purposes is 8*1.772 (at most) = 14.176 inches


The amp0 rod is 8 by 3/8 of an inch,  volume is 0.88357 inches^3 (14.479 cm^3)
So 2378 J per in^3, or 145.823 J/cm^3.  The max optical population inversion
is 4J/cm^3, but that is optical not electrical.  I suspect we are nowhere near
that number given that the 10J version of the laser has 4 lamps in its amp.

Osc exit beam may be 1/8 inch diameter...  assuming 1/8 input (wrong)  
a 1/8 by 8 inch rod  is .0981747696 in^2  a 1/4 by 8 inch rod is .3926990784,
which is 4x larger.  IE: a larger beam in the amp may quadruple output.



New amp rod is 6.125 by 0.3750 (measured) inches volume is 0.6764 inches^3 (11.08421 cm^3)
so at least  1609 J to achieve the same energy density as the current amp.  Except that
we really want more than that.

1602 joules is 3600 volts in 250 uF.  Which is way too much. According to the pfncalc1
spreadsheet, we don't want to exceed 2000V in 250 uF.  Which is 500 joules per lamp.


If we use the 2400V number, then we need 1050 jouls total, or 525 per lamp.  2000V
is 1000 J into the pair of lamps, which should be the same energy density as amp0.
Push it to 2100V, and thats 1102 J total.

Except that it seems to suck...  I suspect the pump chamber just isn't very reflective.


150mm by 7mm OD lamp.  Assume 1mm wall thickness so arc is 150mm by 5mm diameter.
overall 11.375 inches.
Ko=38.4  
explosion energy constant 184000   (not joules...)
max avg power 4713 watts  800 amps
min voltage 900
max voltage 3150


min trigger is 18Kv for 150mm

main cap is 250 uF   rated for 5000V    

series trigger, have a story to get 20kV, but not 40

Would like a 560usec pump flash, to match the existing components.



Enter Energy (J): 5000
Enter Pulse Duration (us): 560
Enter Lamp Impedance Ko (ohms-A^.5): 54.8
Enter Lamp arc length (mm): 300
Enter Lamp arc diameter (mm): 7

C = 0.000251067 F  -or-  251.067 uF
V = 6311.096 volts                              <------ too high
L = 138.785 uH
Zo = 0.743
Ipk = 386.374 amps
explosion energy u= 176084.891 Joules
Eo/u = 0.028 , life expectancy of >10^6 pulses (maybe)




Enter Energy (J): 2500
Enter Pulse Duration (us): 500
Enter Lamp Impedance Ko (ohms-A^.5): 27.4
Enter Lamp arc length (mm): 150
Enter Lamp arc diameter (mm): 7

C = 0.000465595 F  -or-  465.595 uF        <---- too high
V = 3277.033 volts
L = 59.661 uH
Zo = 0.358
Ipk = 401.927 amps
explosion energy u= 83192.289 Joules
Eo/u = 0.030 , life expectancy of >10^6 pulses (maybe)


150mm by 6mm ID   Ko=32.0

Enter Energy (J): 2500
Enter Pulse Duration (us): 560
Enter Lamp Impedance Ko (ohms-A^.5): 32
Enter Lamp arc length (mm): 15
Enter Lamp arc diameter (mm): 6

C = 0.000408277 F  -or-  408.277 uF
V = 3499.514 volts
L = 85.345 uH
Zo = 0.457
Ipk = 2304.982 amps
explosion energy u= 7546.496 Joules
Eo/u = 0.331 , life expectancy of 10^4 - 10^6 pulses (maybe)



150mm by 5mm ID  Ko=38.4    explosion energy 184000

Enter Energy (J): 2500
Enter Pulse Duration (us): 560
Enter Lamp Impedance Ko (ohms-A^.5): 38.4
Enter Lamp arc length (mm): 150
Enter Lamp arc diameter (mm): 5

C = 0.000320169 F  -or-  320.169 uF
V = 3951.803 volts
L = 108.831 uH
Zo = 0.583
Ipk = 249.138 amps
explosion energy u= 62887.461 Joules
Eo/u = 0.040 , life expectancy of >10^6 pulses (maybe)


shorten the pulse a bunch...

Enter Energy (J): 2500
Enter Pulse Duration (us): 400
Enter Lamp Impedance Ko (ohms-A^.5): 38.4
Enter Lamp arc length (mm): 150
Enter Lamp arc diameter (mm): 5

C = 0.000255836 F  -or-  255.836 uF		<----- close enough
V = 4420.838 volts				<-----  kinda at the rating
L = 69.489 uH
Zo = 0.521
Ipk = 279.799 amps
explosion energy u= 53149.605 Joules
Eo/u = 0.047 , life expectancy of >10^6 pulses (maybe)




This is for one lamp:

Enter Energy (J): 1610
Enter Pulse Duration (us): 500
Enter Lamp Impedance Ko (ohms-A^.5): 38.4
Enter Lamp arc length (mm): 150
Enter Lamp arc diameter (mm): 5

C = 0.000256367 F  -or-  256.367 uF		<-- close enough
V = 3544.023 volts				<-- good for cap, might need to adjust controller scale 
L = 108.351 uH
Zo = 0.650
Ipk = 222.489 amps
explosion energy u= 59423.066 Joules
Eo/u = 0.027 , life expectancy of >10^6 pulses (maybe)

Enter Energy (J): 1700
Enter Pulse Duration (us): 500
Enter Lamp Impedance Ko (ohms-A^.5): 38.4
Enter Lamp arc length (mm): 150
Enter Lamp arc diameter (mm): 5

C = 0.000261058 F  -or-  261.058 uF
V = 3608.867 volts
L = 106.405 uH
Zo = 0.638
Ipk = 226.726 amps
explosion energy u= 59423.066 Joules
Eo/u = 0.029 , life expectancy of >10^6 pulses (maybe)

Enter Energy (J): 2000
Enter Pulse Duration (us): 490
Enter Lamp Impedance Ko (ohms-A^.5): 38.4
Enter Lamp arc length (mm): 150
Enter Lamp arc diameter (mm): 5

C = 0.000271904 F  -or-  271.904 uF
V = 3835.505 volts
L = 98.115 uH
Zo = 0.601
Ipk = 241.537 amps
explosion energy u= 58825.836 Joules
Eo/u = 0.034 , life expectancy of >10^6 pulses (maybe)


To make a 100uH inductor, 2 inches in diameter and 1.33 inches long (35mm), 
one needs 47 turns.  The purple wire (16 gauge) is 0.120 inches in diameter
so about 11 turns per layer.  so about 4 layers.
White wire (12 gauge) is 0.125 in diameter. 

Made a 3 inch diameter by 0.63 in wide coil with about 30 turns, got an
induction of 60 uH.  Which is half the value I was hoping for and that
the coil program predicted.  I suspect the insulation thickness threw
it off.  However it might be usable for the isolation inductor.  (spec is 12 uH)

Tried again, 2 inch ID by 0.63 in wide coil with maybe 36 turns (felt like more)
induction is 75 uH.  both in series and held together, 184 uH.

3 inch ID  1.33 inch wide  31 turns is 84 uH
3 inch ID 1.33 in wide 61 turns is 340 uH
Got a 120 uH coil by unwinding the 61 turn one a bunch.  Made the 84 uH one with
the removed wire.

400V power supply schematic
http://imajeenyus.com/electronics/20111010_40-400V_supply/
